H5如何實(shí)現(xiàn)旋轉(zhuǎn)立體魔方?這個(gè)問(wèn)題可能是我們?nèi)粘W(xué)習(xí)或工作經(jīng)常見(jiàn)到的。希望通過(guò)這個(gè)問(wèn)題能讓你收獲頗深。下面是小編給大家?guī)?lái)的參考內(nèi)容,讓我們一起來(lái)看看吧!
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下面是預(yù)覽畫(huà)面。
制作流程
首先你需要下載Html5開(kāi)源庫(kù)件lufylegend-1.4.0
魔方分為6個(gè)面,每個(gè)面由9個(gè)小矩形組成,現(xiàn)在我把每個(gè)小矩形當(dāng)做一個(gè)類(lèi)封裝起來(lái),
因?yàn)楝F(xiàn)在建立的是一個(gè)3D魔方,所以要畫(huà)出每個(gè)小矩形,需要知道小矩形的4個(gè)定點(diǎn),而這4個(gè)定點(diǎn)會(huì)根據(jù)空間的旋轉(zhuǎn)角度而變換,所以為了計(jì)算出這4個(gè)定點(diǎn)坐標(biāo),需要知道魔方繞x軸和z軸旋轉(zhuǎn)的角度。
所以,建立矩形類(lèi)如下
function Rect(pointA,pointB,pointC,pointD,angleX,angleZ,color){ base(this,LSprite,[]); this.pointZ=[(pointA[0]+pointB[0]+pointC[0]+pointD[0])/4,(pointA[1]+pointB[1]+pointC[1]+pointD[1])/4,(pointA[2]+pointB[2]+pointC[2]+pointD[2])/4]; this.z = this.pointZ[2]; this.pointA=pointA,this.pointB=pointB,this.pointC=pointC,this.pointD=pointD,this.angleX=angleX,this.angleZ=angleZ,this.color=color; } Rect.prototype.setAngle = function(a,b){ this.angleX = a; this.angleZ = b; this.z=this.getPoint(this.pointZ)[2]; };
pointA,pointB,pointC,pointD是小矩形的四個(gè)頂點(diǎn),angleX,angleZ分別是x軸和z軸旋轉(zhuǎn)的角度,color是小矩形的顏色。
魔方分為6個(gè)面,先看一下最前面的一面,如果以立方體的中心作為3D坐標(biāo)系的中心,那么9個(gè)小矩形的各個(gè)定點(diǎn)所對(duì)應(yīng)的坐標(biāo)如下圖所示
所以,前面這個(gè)面的9個(gè)小矩形可以由下面的代碼來(lái)建立
for(var x=0;x<3;x++){ for(var y=0;y<3;y++){ z = 3; var rect = new Rect([-3*step + x*2*step,-3*step + y*2*step,-3*step + z*2*step],[-step + x*2*step,-3*step + y*2*step,-3*step + z*2*step],[-step + x*2*step,-step + y*2*step,-3*step + z*2*step],[-3*step + x*2*step,-step + y*2*step,-3*step + z*2*step],0,0,"#FF0000"); backLayer.addChild(rect); } }
其中backLayer是一個(gè)LSprite類(lèi),step是半個(gè)小矩形的長(zhǎng),同樣的道理,可以也得到其他5個(gè)面。
6個(gè)面都建立了,在繪制這6個(gè)面之前,首先要根據(jù)旋轉(zhuǎn)的角度來(lái)計(jì)算各個(gè)定點(diǎn)的坐標(biāo),看下面的圖
根據(jù)上面的圖,用下面的公式即可得到變換后的定點(diǎn)坐標(biāo)
Rect.prototype.getPoint = function(p){ var u2,v2,w2,u=p[0],v=p[1],w=p[2]; u2 = u * Math.cos(this.angleX) - v * Math.sin(this.angleX); v2 = u * Math.sin(this.angleX) + v * Math.cos(this.angleX); w2 = w; u = u2; v = v2; w = w2; u2 = u; v2 = v * Math.cos(this.angleZ) - w * Math.sin(this.angleZ); w2 = v * Math.sin(this.angleZ) + w * Math.cos(this.angleZ); u = u2; v = v2; w = w2; return [u2,v2,w2]; };
最后根據(jù)小矩形的四個(gè)定點(diǎn)坐標(biāo),來(lái)繪制這個(gè)矩形,
Rect.prototype.draw = function(layer){ this.graphics.clear(); this.graphics.drawVertices(1,"#000000",[this.getPoint(this.pointA),this.getPoint(this.pointB),this.getPoint(this.pointC),this.getPoint(this.pointD)],true,this.color); };
其中drawVertices是lufylegend.js庫(kù)件中LGraphics類(lèi)的一個(gè)方法,它可以根據(jù)傳入的定點(diǎn)坐標(biāo)數(shù)組來(lái)繪制一個(gè)多邊形。
最后,給出完整代碼,代碼很少,JS代碼一共91行。
一,index.html
<!DOCTYPE html> <html> <head> <meta charset="UTF-8"> <title>3D魔方</title> </head> <body> <p id="mylegend">loading……</p> <script type="text/javascript" src="../lufylegend-1.4.0.min.js"></script> <script type="text/javascript" src="./Main.js"></script> <script type="text/javascript" src="./Rect.js"></script> </body> </html>
二,Rect類(lèi)
function Rect(pointA,pointB,pointC,pointD,angleX,angleZ,color){ base(this,LSprite,[]); this.pointZ=[(pointA[0]+pointB[0]+pointC[0]+pointD[0])/4,(pointA[1]+pointB[1]+pointC[1]+pointD[1])/4,(pointA[2]+pointB[2]+pointC[2]+pointD[2])/4]; this.z = this.pointZ[2]; this.pointA=pointA,this.pointB=pointB,this.pointC=pointC,this.pointD=pointD,this.angleX=angleX,this.angleZ=angleZ,this.color=color; } Rect.prototype.draw = function(layer){ this.graphics.clear(); this.graphics.drawVertices(1,"#000000",[this.getPoint(this.pointA),this.getPoint(this.pointB),this.getPoint(this.pointC),this.getPoint(this.pointD)],true,this.color); }; Rect.prototype.setAngle = function(a,b){ this.angleX = a; this.angleZ = b; this.z=this.getPoint(this.pointZ)[2]; }; Rect.prototype.getPoint = function(p){ var u2,v2,w2,u=p[0],v=p[1],w=p[2]; u2 = u * Math.cos(this.angleX) - v * Math.sin(this.angleX); v2 = u * Math.sin(this.angleX) + v * Math.cos(this.angleX); w2 = w; u = u2; v = v2; w = w2; u2 = u; v2 = v * Math.cos(this.angleZ) - w * Math.sin(this.angleZ); w2 = v * Math.sin(this.angleZ) + w * Math.cos(this.angleZ); u = u2; v = v2; w = w2; return [u2,v2,w2]; };
三,Main.js
init(50,"mylegend",400,400,main); var a = 0,b=0,backLayer,step = 20,key = null; function main(){ backLayer = new LSprite(); addChild(backLayer); backLayer.x = 120,backLayer.y = 120; //后 for(var x=0;x<3;x++){ for(var y=0;y<3;y++){ z = 0; var rect = new Rect([-3*step + x*2*step,-3*step + y*2*step,-3*step + z*2*step],[-step + x*2*step,-3*step + y*2*step,-3*step + z*2*step],[-step + x*2*step,-step + y*2*step,-3*step + z*2*step],[-3*step + x*2*step,-step + y*2*step,-3*step + z*2*step],0,0,"#FF4500"); backLayer.addChild(rect); } } //前 for(var x=0;x<3;x++){ for(var y=0;y<3;y++){ z = 3; var rect = new Rect([-3*step + x*2*step,-3*step + y*2*step,-3*step + z*2*step],[-step + x*2*step,-3*step + y*2*step,-3*step + z*2*step],[-step + x*2*step,-step + y*2*step,-3*step + z*2*step],[-3*step + x*2*step,-step + y*2*step,-3*step + z*2*step],0,0,"#FF0000"); backLayer.addChild(rect); } } //上 for(var x=0;x<3;x++){ for(var z=0;z<3;z++){ y = 0; var rect = new Rect([-3*step + x*2*step,-3*step + y*2*step,-3*step + z*2*step],[-step + x*2*step,-3*step + y*2*step,-3*step + z*2*step],[-step + x*2*step,-3*step + y*2*step,-step + z*2*step],[-3*step + x*2*step,-3*step + y*2*step,-step + z*2*step],0,0,"#FFFFFF"); backLayer.addChild(rect); } } //下 for(var x=0;x<3;x++){ for(var z=0;z<3;z++){ y = 3; var rect = new Rect([-3*step + x*2*step,-3*step + y*2*step,-3*step + z*2*step],[-step + x*2*step,-3*step + y*2*step,-3*step + z*2*step],[-step + x*2*step,-3*step + y*2*step,-step + z*2*step],[-3*step + x*2*step,-3*step + y*2*step,-step + z*2*step],0,0,"#FFFF00"); backLayer.addChild(rect); } } //左 for(var y=0;y<3;y++){ for(var z=0;z<3;z++){ x = 0; var rect = new Rect([-3*step + x*2*step,-3*step + y*2*step,-3*step + z*2*step],[-3*step + x*2*step,-3*step + y*2*step,-step + z*2*step],[-3*step + x*2*step,-step + y*2*step,-step + z*2*step],[-3*step + x*2*step,-step + y*2*step,-3*step + z*2*step],0,0,"#008000"); backLayer.addChild(rect); } } //右 for(var y=0;y<3;y++){ for(var z=0;z<3;z++){ x = 3; var rect = new Rect([-3*step + x*2*step,-3*step + y*2*step,-3*step + z*2*step],[-3*step + x*2*step,-3*step + y*2*step,-step + z*2*step],[-3*step + x*2*step,-step + y*2*step,-step + z*2*step],[-3*step + x*2*step,-step + y*2*step,-3*step + z*2*step],0,0,"#0000FF"); backLayer.addChild(rect); } } backLayer.addEventListener(LEvent.ENTER_FRAME,onframe); } function onframe(){ a += 0.1 , b += 0.1; backLayer.childList = backLayer.childList.sort(function(a,b){return a.z - b.z;}); for(key in backLayer.childList){ backLayer.childList[key].setAngle(a,b); backLayer.childList[key].draw(backLayer); } }
感謝各位的閱讀!看完上述內(nèi)容,你們對(duì)H5如何實(shí)現(xiàn)旋轉(zhuǎn)立體魔方大概了解了嗎?希望文章內(nèi)容對(duì)大家有所幫助。如果想了解更多相關(guān)文章內(nèi)容,歡迎關(guān)注創(chuàng)新互聯(lián)行業(yè)資訊頻道。
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