請教MD5算法 用C語言實現(xiàn)

#include?stdio.h

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#include?stdlib.h

#include?string.h

#if?defined(__APPLE__)

#??define?COMMON_DIGEST_FOR_OPENSSL

#??include?CommonCrypto/CommonDigest.h

#??define?SHA1?CC_SHA1

#else

#??include?openssl/md5.h

#endif

//?這是我自己寫的函數，用于計算MD5

//?參數?str：要轉換的字符串

//?參數?lengthL:?字符串的長度?可以用?strlen(str)?直接獲取參數str的長度

//?返回值：MD5字符串

char?*str2md5(const?char?*?str,?int?length)?{

int?n;

MD5_CTX?c;

unsigned?char?digest[16];

char?*out?=?(char*)malloc(33);

MD5_Init(c);

while?(length??0)?{

if?(length??512)?{

MD5_Update(c,?str,?512);

}?else?{

MD5_Update(c,?str,?length);

}

length?-=?512;

str?+=?512;

}

MD5_Final(digest,?c);

for?(n?=?0;?n??16;?++n)?{

snprintf((out[n*2]),?16*2,?"%02x",?(unsigned?int)digest[n]);

}

return?out;

}

int?main(int?argc,?char?**argv)?{

char?*output?=?str2md5("hello",?strlen("hello"));

printf("%s\n",?output);

//?上面會輸出?hello的MD5字符串：

//?5d41402abc4b2a76b9719d911017c592

free(output);

return?0;

}

C語言 MD5加密

main.cpp

#include stdio.h

#include string.h

#include stdlib.h

#include "md5.c"

int main(int argc, char* argv[])

{

int i;

unsigned char encrypt[] = "admin";//21232f297a57a5a743894a0e4a801fc3

unsigned char decrypt[16];

MD5_CTX md5;

MD5Init(md5);

MD5Update(md5, encrypt, strlen((char*)encrypt));

MD5Final(md5, decrypt);

printf("加密前:%s\n加密后:", encrypt);

for (i = 0; i 16; i++)

{

printf("%02x", decrypt[i]);

}

getchar();

return 0;

}

md5.c

#include memory.h

#include "md5.h"

unsigned char PADDING[] = { 0x80,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

? ? ? ? ? ? ? ? ? ? 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

? ? ? ? ? ? ? ? ? ? 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

? ? ? ? ? ? ? ? ? ? 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0 };

void MD5Init(MD5_CTX* context)

{

context-count[0] = 0;

context-count[1] = 0;

context-state[0] = 0x67452301;

context-state[1] = 0xEFCDAB89;

context-state[2] = 0x98BADCFE;

context-state[3] = 0x10325476;

}

void MD5Update(MD5_CTX* context, unsigned char* input, unsigned int inputlen)

{

unsigned int i = 0, index = 0, partlen = 0;

index = (context-count[0] 3) 0x3F;

partlen = 64 - index;

context-count[0] += inputlen 3;

if (context-count[0] (inputlen 3))

? ? context-count[1]++;

context-count[1] += inputlen 29;

if (inputlen = partlen)

{

? ? memcpy(context-buffer[index], input, partlen);

? ? MD5Transform(context-state, context-buffer);

? ? for (i = partlen; i + 64 = inputlen; i += 64)

? ? ? ? MD5Transform(context-state, input[i]);

? ? index = 0;

}

else

{

? ? i = 0;

}

memcpy(context-buffer[index], input[i], inputlen - i);

}

void MD5Final(MD5_CTX* context, unsigned char digest[16])

{

unsigned int index = 0, padlen = 0;

unsigned char bits[8];

index = (context-count[0] 3) 0x3F;

padlen = (index 56) ? (56 - index) : (120 - index);

MD5Encode(bits, context-count, 8);

MD5Update(context, PADDING, padlen);

MD5Update(context, bits, 8);

MD5Encode(digest, context-state, 16);

}

void MD5Encode(unsigned char* output, unsigned int* input, unsigned int len)

{

unsigned int i = 0, j = 0;

while (j len)

{

? ? output[j] = input[i] 0xFF;

? ? output[j + 1] = (input[i] 8) 0xFF;

? ? output[j + 2] = (input[i] 16) 0xFF;

? ? output[j + 3] = (input[i] 24) 0xFF;

? ? i++;

? ? j += 4;

}

}

void MD5Decode(unsigned int* output, unsigned char* input, unsigned int len)

{

unsigned int i = 0, j = 0;

while (j len)

{

? ? output[i] = (input[j]) |

? ? ? ? (input[j + 1] 8) |

? ? ? ? (input[j + 2] 16) |

? ? ? ? (input[j + 3] 24);

? ? i++;

? ? j += 4;

}

}

void MD5Transform(unsigned int state[4], unsigned char block[64])

{

unsigned int a = state[0];

unsigned int b = state[1];

unsigned int c = state[2];

unsigned int d = state[3];

unsigned int x[64];

MD5Decode(x, block, 64);

FF(a, b, c, d, x[0], 7, 0xd76aa478); /* 1 */

FF(d, a, b, c, x[1], 12, 0xe8c7b756); /* 2 */

FF(c, d, a, b, x[2], 17, 0x242070db); /* 3 */

FF(b, c, d, a, x[3], 22, 0xc1bdceee); /* 4 */

FF(a, b, c, d, x[4], 7, 0xf57c0faf); /* 5 */

FF(d, a, b, c, x[5], 12, 0x4787c62a); /* 6 */

FF(c, d, a, b, x[6], 17, 0xa8304613); /* 7 */

FF(b, c, d, a, x[7], 22, 0xfd469501); /* 8 */

FF(a, b, c, d, x[8], 7, 0x698098d8); /* 9 */

FF(d, a, b, c, x[9], 12, 0x8b44f7af); /* 10 */

FF(c, d, a, b, x[10], 17, 0xffff5bb1); /* 11 */

FF(b, c, d, a, x[11], 22, 0x895cd7be); /* 12 */

FF(a, b, c, d, x[12], 7, 0x6b901122); /* 13 */

FF(d, a, b, c, x[13], 12, 0xfd987193); /* 14 */

FF(c, d, a, b, x[14], 17, 0xa679438e); /* 15 */

FF(b, c, d, a, x[15], 22, 0x49b40821); /* 16 */

/* Round 2 */

GG(a, b, c, d, x[1], 5, 0xf61e2562); /* 17 */

GG(d, a, b, c, x[6], 9, 0xc040b340); /* 18 */

GG(c, d, a, b, x[11], 14, 0x265e5a51); /* 19 */

GG(b, c, d, a, x[0], 20, 0xe9b6c7aa); /* 20 */

GG(a, b, c, d, x[5], 5, 0xd62f105d); /* 21 */

GG(d, a, b, c, x[10], 9, 0x2441453); /* 22 */

GG(c, d, a, b, x[15], 14, 0xd8a1e681); /* 23 */

GG(b, c, d, a, x[4], 20, 0xe7d3fbc8); /* 24 */

GG(a, b, c, d, x[9], 5, 0x21e1cde6); /* 25 */

GG(d, a, b, c, x[14], 9, 0xc33707d6); /* 26 */

GG(c, d, a, b, x[3], 14, 0xf4d50d87); /* 27 */

GG(b, c, d, a, x[8], 20, 0x455a14ed); /* 28 */

GG(a, b, c, d, x[13], 5, 0xa9e3e905); /* 29 */

GG(d, a, b, c, x[2], 9, 0xfcefa3f8); /* 30 */

GG(c, d, a, b, x[7], 14, 0x676f02d9); /* 31 */

GG(b, c, d, a, x[12], 20, 0x8d2a4c8a); /* 32 */

/* Round 3 */

HH(a, b, c, d, x[5], 4, 0xfffa3942); /* 33 */

HH(d, a, b, c, x[8], 11, 0x8771f681); /* 34 */

HH(c, d, a, b, x[11], 16, 0x6d9d6122); /* 35 */

HH(b, c, d, a, x[14], 23, 0xfde5380c); /* 36 */

HH(a, b, c, d, x[1], 4, 0xa4beea44); /* 37 */

HH(d, a, b, c, x[4], 11, 0x4bdecfa9); /* 38 */

HH(c, d, a, b, x[7], 16, 0xf6bb4b60); /* 39 */

HH(b, c, d, a, x[10], 23, 0xbebfbc70); /* 40 */

HH(a, b, c, d, x[13], 4, 0x289b7ec6); /* 41 */

HH(d, a, b, c, x[0], 11, 0xeaa127fa); /* 42 */

HH(c, d, a, b, x[3], 16, 0xd4ef3085); /* 43 */

HH(b, c, d, a, x[6], 23, 0x4881d05); /* 44 */

HH(a, b, c, d, x[9], 4, 0xd9d4d039); /* 45 */

HH(d, a, b, c, x[12], 11, 0xe6db99e5); /* 46 */

HH(c, d, a, b, x[15], 16, 0x1fa27cf8); /* 47 */

HH(b, c, d, a, x[2], 23, 0xc4ac5665); /* 48 */

/* Round 4 */

II(a, b, c, d, x[0], 6, 0xf4292244); /* 49 */

II(d, a, b, c, x[7], 10, 0x432aff97); /* 50 */

II(c, d, a, b, x[14], 15, 0xab9423a7); /* 51 */

II(b, c, d, a, x[5], 21, 0xfc93a039); /* 52 */

II(a, b, c, d, x[12], 6, 0x655b59c3); /* 53 */

II(d, a, b, c, x[3], 10, 0x8f0ccc92); /* 54 */

II(c, d, a, b, x[10], 15, 0xffeff47d); /* 55 */

II(b, c, d, a, x[1], 21, 0x85845dd1); /* 56 */

II(a, b, c, d, x[8], 6, 0x6fa87e4f); /* 57 */

II(d, a, b, c, x[15], 10, 0xfe2ce6e0); /* 58 */

II(c, d, a, b, x[6], 15, 0xa3014314); /* 59 */

II(b, c, d, a, x[13], 21, 0x4e0811a1); /* 60 */

II(a, b, c, d, x[4], 6, 0xf7537e82); /* 61 */

II(d, a, b, c, x[11], 10, 0xbd3af235); /* 62 */

II(c, d, a, b, x[2], 15, 0x2ad7d2bb); /* 63 */

II(b, c, d, a, x[9], 21, 0xeb86d391); /* 64 */

state[0] += a;

state[1] += b;

state[2] += c;

state[3] += d;

}

md5.h

#ifndef MD5_H

#define MD5_H

typedef struct

{

unsigned int count[2];

unsigned int state[4];

unsigned char buffer[64];

}MD5_CTX;

#define F(x,y,z) ((x y) | (~x z))

#define G(x,y,z) ((x z) | (y ~z))

#define H(x,y,z) (x^y^z)

#define I(x,y,z) (y ^ (x | ~z))

#define ROTATE_LEFT(x,n) ((x n) | (x (32-n)))

#define FF(a,b,c,d,x,s,ac) \

? ? ? { \

? ? ? a += F(b,c,d) + x + ac; \

? ? ? a = ROTATE_LEFT(a,s); \

? ? ? a += b; \

? ? ? }

#define GG(a,b,c,d,x,s,ac) \

? ? ? { \

? ? ? a += G(b,c,d) + x + ac; \

? ? ? a = ROTATE_LEFT(a,s); \

? ? ? a += b; \

? ? ? }

#define HH(a,b,c,d,x,s,ac) \

? ? ? { \

? ? ? a += H(b,c,d) + x + ac; \

? ? ? a = ROTATE_LEFT(a,s); \

? ? ? a += b; \

? ? ? }

#define II(a,b,c,d,x,s,ac) \

? ? ? { \

? ? ? a += I(b,c,d) + x + ac; \

? ? ? a = ROTATE_LEFT(a,s); \

? ? ? a += b; \

? ? ? }

void MD5Init(MD5_CTX* context);

void MD5Update(MD5_CTX* context, unsigned char* input, unsigned int inputlen);

void MD5Final(MD5_CTX* context, unsigned char digest[16]);

void MD5Transform(unsigned int state[4], unsigned char block[64]);

void MD5Encode(unsigned char* output, unsigned int* input, unsigned int len);

void MD5Decode(unsigned int* output, unsigned char* input, unsigned int len);

#endif

VS2013中c語言md5加密函數怎么調用?

1、主要就是調用庫函數，MD5加密說到底也是函數計算，沒有什么思路的問題，了解md5的發(fā)明算法，本質是一個數學問題。

2、例程：

#ifndef?MD5_H

#define?MD5_H

typedef?struct

{

unsigned?int?count[2];

unsigned?int?state[4];

unsigned?char?buffer[64];???

}MD5_CTX;

#define?F(x,y,z)?((x??y)?|?(~x??z))

#define?G(x,y,z)?((x??z)?|?(y??~z))

#define?H(x,y,z)?(x^y^z)

#define?I(x,y,z)?(y?^?(x?|?~z))

#define?ROTATE_LEFT(x,n)?((x??n)?|?(x??(32-n)))

#define?FF(a,b,c,d,x,s,ac)?\

{?\

a?+=?F(b,c,d)?+?x?+?ac;?\

a?=?ROTATE_LEFT(a,s);?\

a?+=?b;?\

}

#define?GG(a,b,c,d,x,s,ac)?\

{?\

a?+=?G(b,c,d)?+?x?+?ac;?\

a?=?ROTATE_LEFT(a,s);?\

a?+=?b;?\

}

#define?HH(a,b,c,d,x,s,ac)?\

{?\

a?+=?H(b,c,d)?+?x?+?ac;?\

a?=?ROTATE_LEFT(a,s);?\

a?+=?b;?\

}

#define?II(a,b,c,d,x,s,ac)?\

{?\

a?+=?I(b,c,d)?+?x?+?ac;?\

a?=?ROTATE_LEFT(a,s);?\

a?+=?b;?\

}????????????????????????????????????????????

void?MD5Init(MD5_CTX?*context);

void?MD5Update(MD5_CTX?*context,unsigned?char?*input,unsigned?int?inputlen);

void?MD5Final(MD5_CTX?*context,unsigned?char?digest[16]);

void?MD5Transform(unsigned?int?state[4],unsigned?char?block[64]);

void?MD5Encode(unsigned?char?*output,unsigned?int?*input,unsigned?int?len);

void?MD5Decode(unsigned?int?*output,unsigned?char?*input,unsigned?int?len);

#endif

源文件md5.c

#include?memory.h

#include?"md5.h"

unsigned?char?PADDING[]={0x80,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};

void?MD5Init(MD5_CTX?*context)

{

context-count[0]?=?0;

context-count[1]?=?0;

context-state[0]?=?0x67452301;

context-state[1]?=?0xEFCDAB89;

context-state[2]?=?0x98BADCFE;

context-state[3]?=?0x10325476;

}

void?MD5Update(MD5_CTX?*context,unsigned?char?*input,unsigned?int?inputlen)

{

unsigned?int?i?=?0,index?=?0,partlen?=?0;

index?=?(context-count[0]??3)??0x3F;

partlen?=?64?-?index;

context-count[0]?+=?inputlen??3;

if(context-count[0]??(inputlen??3))

context-count[1]++;

context-count[1]?+=?inputlen??29;

if(inputlen?=?partlen)

{

memcpy(context-buffer[index],input,partlen);

MD5Transform(context-state,context-buffer);

for(i?=?partlen;i+64?=?inputlen;i+=64)

MD5Transform(context-state,input[i]);

index?=?0;????????

}??

else

{

i?=?0;

}

memcpy(context-buffer[index],input[i],inputlen-i);

}

void?MD5Final(MD5_CTX?*context,unsigned?char?digest[16])

{

unsigned?int?index?=?0,padlen?=?0;

unsigned?char?bits[8];

index?=?(context-count[0]??3)??0x3F;

padlen?=?(index??56)?(56-index):(120-index);

MD5Encode(bits,context-count,8);

MD5Update(context,PADDING,padlen);

MD5Update(context,bits,8);

MD5Encode(digest,context-state,16);

}

void?MD5Encode(unsigned?char?*output,unsigned?int?*input,unsigned?int?len)

{

unsigned?int?i?=?0,j?=?0;

while(j??len)

{

output[j]?=?input[i]??0xFF;??

output[j+1]?=?(input[i]??8)??0xFF;

output[j+2]?=?(input[i]??16)??0xFF;

output[j+3]?=?(input[i]??24)??0xFF;

i++;

j+=4;

}

}

void?MD5Decode(unsigned?int?*output,unsigned?char?*input,unsigned?int?len)

{

unsigned?int?i?=?0,j?=?0;

while(j??len)

{

output[i]?=?(input[j])?|

(input[j+1]??8)?|

(input[j+2]??16)?|

(input[j+3]??24);

i++;

j+=4;?

}

}

void?MD5Transform(unsigned?int?state[4],unsigned?char?block[64])

{

unsigned?int?a?=?state[0];

unsigned?int?b?=?state[1];

unsigned?int?c?=?state[2];

unsigned?int?d?=?state[3];

unsigned?int?x[64];

MD5Decode(x,block,64);

FF(a,?b,?c,?d,?x[?0],?7,?0xd76aa478);?/*?1?*/

FF(d,?a,?b,?c,?x[?1],?12,?0xe8c7b756);?/*?2?*/

FF(c,?d,?a,?b,?x[?2],?17,?0x242070db);?/*?3?*/

FF(b,?c,?d,?a,?x[?3],?22,?0xc1bdceee);?/*?4?*/

FF(a,?b,?c,?d,?x[?4],?7,?0xf57c0faf);?/*?5?*/

FF(d,?a,?b,?c,?x[?5],?12,?0x4787c62a);?/*?6?*/

FF(c,?d,?a,?b,?x[?6],?17,?0xa8304613);?/*?7?*/

FF(b,?c,?d,?a,?x[?7],?22,?0xfd469501);?/*?8?*/

FF(a,?b,?c,?d,?x[?8],?7,?0x698098d8);?/*?9?*/

FF(d,?a,?b,?c,?x[?9],?12,?0x8b44f7af);?/*?10?*/

FF(c,?d,?a,?b,?x[10],?17,?0xffff5bb1);?/*?11?*/

FF(b,?c,?d,?a,?x[11],?22,?0x895cd7be);?/*?12?*/

FF(a,?b,?c,?d,?x[12],?7,?0x6b901122);?/*?13?*/

FF(d,?a,?b,?c,?x[13],?12,?0xfd987193);?/*?14?*/

FF(c,?d,?a,?b,?x[14],?17,?0xa679438e);?/*?15?*/

FF(b,?c,?d,?a,?x[15],?22,?0x49b40821);?/*?16?*/

如何對字符串進行MD5加密,用C語言實現(xiàn),給出源代碼和加密函數

#include stdio.h

#define S11 7

#define S12 12

#define S13 17

#define S14 22

#define S21 5

#define S22 9

#define S23 14

#define S24 20

#define S31 4

#define S32 11

#define S33 16

#define S34 23

#define S41 6

#define S42 10

#define S43 15

#define S44 21

#define R_memset(x, y, z) memset(x, y, z)

#define R_memcpy(x, y, z) memcpy(x, y, z)

#define R_memcmp(x, y, z) memcmp(x, y, z)

typedef unsigned long UINT4;

typedef unsigned char *POINTER;

typedef struct {

/*四個32bits數,用于存放最終計算得到的消息摘要.當消息長度512bits時,也用于存放每個512bits的中間結果*/

UINT4 state[4];

/*存儲原始信息的bits數長度,不包括填充的bits,最長為2^64 bits*/

UINT4 count[2];

/*存放輸入的信息的緩沖區(qū),512bits*/

unsigned char buffer[64];

} MD5_CTX;

static void MD5Transform(UINT4[4], unsigned char[64]);

static void Encode(unsigned char *, UINT4 *, unsigned int);

static void Decode(UINT4 *, unsigned char *, unsigned int);

/*

用于bits填充的緩沖區(qū),當欲加密的信息的bits數被512除其余數為448時,需要填充的bits的最大值為512=64*8*/

static unsigned char PADDING[64] = {

0x80, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,

0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,

0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0

};

/*接下來的這幾個宏定義是md5算法規(guī)定的,就是對信息進行md5加密都要做的運算*/

#define F(x, y, z) (((x) (y)) | ((~x) (z)))

#define G(x, y, z) (((x) (z)) | ((y) (~z)))

#define H(x, y, z) ((x) ^ (y) ^ (z))

#define I(x, y, z) ((y) ^ ((x) | (~z)))

#define ROTATE_LEFT(x, n) (((x) (n)) | ((x) (32-(n))))

#define FF(a, b, c, d, x, s, ac) {\

(a) += F ((b), (c), (d)) + (x) + (UINT4)(ac);\

(a) = ROTATE_LEFT ((a), (s));\

(a) += (b);\

}

#define GG(a, b, c, d, x, s, ac) {\

(a) += G ((b), (c), (d)) + (x) + (UINT4)(ac);\

(a) = ROTATE_LEFT ((a), (s));\

(a) += (b);\

}

#define HH(a, b, c, d, x, s, ac) {\

(a) += H ((b), (c), (d)) + (x) + (UINT4)(ac);\

(a) = ROTATE_LEFT ((a), (s));\

(a) += (b);\

}

#define II(a, b, c, d, x, s, ac) {\

(a) += I ((b), (c), (d)) + (x) + (UINT4)(ac);\

(a) = ROTATE_LEFT ((a), (s));\

(a) += (b);\

}

當前名稱：c語言md5加密函數 c++md5加密
文章位置：http://www.rwnh.cn/article32/dopppsc.html

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